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Chapter 2 notebook: waves, interfaces, and sheets

Predict first: can a field ratio of 0.8 transmit 96% of the incident power? Can a field exist in a medium while its net normal power is zero? Can adding an interface remove reflection? Can relative phase change absorption?

This notebook answers those questions using exact planar analytical models. It does not discretize a patterned metasurface or run a full-wave geometry solver. Bulk media have positive real constant indices and are nonmagnetic and isotropic. The electric sheet may dissipate power through nonnegative conductance. Use e−iωte^{-i\omega t} and e+ik⋅re^{+i\mathbf k\cdot\mathbf r} throughout.

Topic IDs: ms-01-waves-interfaces, introductory ms-03-sheet-response, and the Jones-vector baseline of ms-06-polarization.

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Environment: 3.12.1 NumPy 2.4.6 Matplotlib 3.11.1

1. Amplitude and power

At z=0z=0 use the same tangential electric-field axis for incident, reflected, and transmitted coefficients. Thus t=1+rt=1+r at a dielectric interface. Use dimensionless Yj=qjY_j=q_j for TE and Yj=nj2/qjY_j=n_j^2/q_j for TM. The physical wave admittance is Yj/η0Y_j/\eta_0, where qj=nj2−n12sin⁡2θiq_j=\sqrt{n_j^2-n_1^2\sin^2\theta_i} has the outgoing/decaying branch.

r=Y1−Y2Y1+Y2,t=2Y1Y1+Y2,R=∣r∣2,T=Re⁡Y2Y1∣t∣2.r=\frac{Y_1-Y_2}{Y_1+Y_2},\quad t=\frac{2Y_1}{Y_1+Y_2},\quad R=|r|^2,\quad T=\frac{\operatorname{Re}Y_2}{Y_1}|t|^2.

The reflected TM coefficient has a sign difference from a convention using a rotated local p basis. At normal incidence both tangential-basis coefficients are r=−0.2r=-0.2, t=0.8t=0.8 for air/glass, giving R=0.04R=0.04, T=0.96T=0.96. Predict the Brewster zero and the glass-to-air critical angle before plotting.

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2. Evanescent fields

For glass to air beyond the critical angle, kz,2=iκk_{z,2}=i\kappa and Et∝eikxxe−κzE_t\propto e^{ik_xx}e^{-\kappa z}. Its nonzero field is not a propagating normal power channel. We reconstruct EyE_y and HxH_x and calculate Sz=−12Re⁡(EyHx∗)S_z=-\tfrac12\operatorname{Re}(E_yH_x^*) directly.

At exact cutoff, TE has tangential t→2t\to2; TM has tangential t→0t\to0. Both give T=0T=0. The latter does not imply that the longitudinal TM field EzE_z vanishes. Undefined phase at zero tangential amplitude is kept separate from zero normal flux of a nonzero evanescent field.

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3. Two reflections can cancel

A normal-incidence film has δ=2πnfd/λ0\delta=2\pi n_fd/\lambda_0, r=(r01+r12e2iδ)/(1+r01r12e2iδ)r=(r_{01}+r_{12}e^{2i\delta})/(1+r_{01}r_{12}e^{2i\delta}). Its transmitted field is referenced at the exit plane, not its entrance. For nf=n1n2n_f=\sqrt{n_1n_2} and d=λ0/(4nf)d=\lambda_0/(4n_f), the reflected terms cancel at the design wavelength. Does unit transmitted power require ∣t∣=1|t|=1?

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<Figure size 1312.5x437.5 with 2 Axes>

4. Follow the electric-field tip

Use the unit Jones vector J=(cos⁡α,sin⁡αeiδ)TJ=(\cos\alpha,\sin\alpha e^{i\delta})^T at a fixed point. With e−iωte^{-i\omega t} the field tip is (cos⁡αcos⁡ωt,sin⁡αcos⁡(δ−ωt))(\cos\alpha\cos\omega t,\sin\alpha\cos(\delta-\omega t)). Define V=2Im⁡(Ex∗Ey)V=2\operatorname{Im}(E_x^*E_y) and report this coordinate convention instead of assigning an ambiguous circular-handedness label. A linear analyzer at β\beta transmits ∣cos⁡βEx+sin⁡βEy∣2|\cos\beta E_x+\sin\beta E_y|^2.

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5. Phase controls absorption

For a coincident-plane electric sheet in air, g=η0Ys=G+iBg=\eta_0Y_s=G+iB, r=−g/(2+g)r=-g/(2+g), t=2/(2+g)t=2/(2+g), and A=G∣t∣2A=G|t|^2. At g=2g=2 one incident wave gives R=T=1/4R=T=1/4 and A=1/2A=1/2. Two equal-power coherent inputs at the same total incident power instead give A2in=(1+cos⁡ϕ)/2A_{2\mathrm{in}}=(1+\cos\phi)/2. The field phases determine excitation of the dissipative even channel or the nondissipative odd channel.

This is an ideal boundary-model result, not a fabricated absorber. The algebraic retrieval g=2(1−t)/tg=2(1-t)/t requires meaningful tt and the sheet constraint t=1+rt=1+r. It cannot be applied to a finite film’s different reference planes indiscriminately.

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A controlled retrieval-error experiment

The inverse is sensitive even when its analytical formula is exact. Sweep passive real shunts in equal air media and add a fixed absolute complex perturbation to transmission. Predict how the inferred parameter error changes as transmission becomes small.

g(t+δt)−g(t)=−2δtt(t+δt),∣δg∣≈2∣δt∣∣t∣2(∣δt∣≪∣t∣).g(t+\delta t)-g(t)=-\frac{2\delta t}{t(t+\delta t)},\qquad |\delta g|\approx\frac{2|\delta t|}{|t|^2}\quad (|\delta t|\ll|t|).

The code compares the exact finite difference with the local derivative estimate. The estimate requires the perturbation to be small relative to transmission, not merely small relative to one. We set the perturbed reflection to the perturbed transmission minus one, so this is a model-consistent synthetic sensitivity experiment. Independent measurement errors in reflection and transmission can also violate continuity and must be checked separately; they are not silently forced into this inverse.

Edit the perturbation magnitude and direction below. Report the ratio of perturbation magnitude to transmission, identify where the linear estimate fails, and distinguish inferred parameters from the original passive sheet. All curves are original calculations from the stated inverse, with no measured or full-wave data.

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Continuity residual if only transmission is perturbed: 0.00010000000000011169
The plotted inverse instead uses model-consistent perturbed r=t-1; independent measurement noise needs its own residual/tolerance model.

6. Audit and export

For propagating ports, power-normalized amplitudes include Y\sqrt{Y}. The lossless film matrix must be unitary and reciprocal. A dissipative sheet must be contractive instead. These are checks of exact planar models; an independent four-boundary-equation film solve and wider parameter audit are provided by scripts/validate_chapter02.py.

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Saved strict JSON and CSV with source hash and explicit reference-plane/model conventions.

Explain the surprises

Compare field amplitude with normal power, zero tangential amplitude with a nonzero evanescent field, and one-sided with two-sided illumination. Explain why quarter-wave antireflection is a spectral/reference-plane statement and why sheet retrieval is a model test before it is an algebraic calculation.

See the Chapter 2 derivations, worked examples, and lab. Extend this baseline to the existing Chapter 3 ridge and Chapter 4 diffraction investigations only after stating the additional geometry, polarization, channels, phase planes, and numerical validation.